Easy · 6×6
🌌 Constellation · Easy #2
You discovered: The Stubborn Sloth
2
🦉 How to solve it
- The teal nebula has only one possible cell: the star goes in A4.
- The pink nebula has only one possible cell: the star goes in B2.
- The red nebula has only one possible cell: the star goes in C6.
- The violet nebula has only one possible cell: the star goes in E5.
- The blue nebula has only one possible cell: the star goes in D3.
- Row 1 has only one possible cell: the star goes in F1.
Medium · 8×8
🌌 Constellation · Medium #2
You discovered: The Lost Hammock
1
🦉 How to solve it
- Every possible cell of the pink nebula is in column C: the rest of that column stays empty.
- Every possible cell of the amber nebula is in column H: the rest of that column stays empty.
- Every possible cell of the red nebula is in row 8: the rest of that row stays empty.
- Every possible cell of the lime nebula is in row 7: the rest of that row stays empty.
- A star in G1 would leave column H with no possible cell: G1 stays empty.
- A star in E2 would leave column G with no possible cell: E2 stays empty.
- A star in F2 would leave column G with no possible cell: F2 stays empty.
- A star in G2 would leave column H with no possible cell: G2 stays empty.
- Column G only has possible cells in the blue nebula: that nebula's star is here, so the rest of it stays empty.
- A star in B3 would leave column C with no possible cell: B3 stays empty.
- A star in D3 would leave column C with no possible cell: D3 stays empty.
- A star in B4 would leave column C with no possible cell: B4 stays empty.
- A star in D4 would leave column C with no possible cell: D4 stays empty.
- A star in E7 would leave row 8 with no possible cell: E7 stays empty.
- Row 7 has only one possible cell: the star goes in D7.
- Row 8 has only one possible cell: the star goes in F8.
- Column E has only one possible cell: the star goes in E1.
- Column H has only one possible cell: the star goes in H2.
- The brown nebula has only one possible cell: the star goes in A3.
- Column C has only one possible cell: the star goes in C4.
- Row 5 has only one possible cell: the star goes in G5.
- Row 6 has only one possible cell: the star goes in B6.
Hard · 9×9
🌌 Constellation · Hard #2
You discovered: The Lovesick Alarm Clock
0
🦉 How to solve it
- The blue nebula has only one possible cell: the star goes in C1.
- The telescope at I1 already sees all its stars: its other neighbors stay empty.
- Every possible cell of the lime nebula is in row 9: the rest of that row stays empty.
- Every possible cell of the brown nebula is in row 8: the rest of that row stays empty.
- A star in H6 would leave the violet nebula with no possible cell: H6 stays empty.
- A star in D7 would leave row 8 with no possible cell: D7 stays empty.
- A star in F6 would leave the red nebula with no possible cell: F6 stays empty.
- A star in E7 would leave row 8 with no possible cell: E7 stays empty.
- A star in G6 would leave the red nebula with no possible cell: G6 stays empty.
- The violet nebula and the red nebula fit entirely in row 6 and row 7: no other nebula can have a star there.
- A star in D3 would leave the teal nebula with no possible cell: D3 stays empty.
- A star in H4 would leave column G with no possible cell: H4 stays empty.
- A star in E5 would leave the teal nebula with no possible cell: E5 stays empty.
- The teal nebula and the amber nebula fit entirely in row 4 and row 5: no other nebula can have a star there.
- The teal nebula and the brown nebula fit entirely in column D and column E: no other nebula can have a star there.
- Row 6 has only one possible cell: the star goes in I6.
- Row 7 has only one possible cell: the star goes in F7.
- Row 8 has only one possible cell: the star goes in D8.
- Row 5 has only one possible cell: the star goes in G5.
- Row 2 has only one possible cell: the star goes in A2.
- Row 3 has only one possible cell: the star goes in H3.
- Row 4 has only one possible cell: the star goes in E4.
- Row 9 has only one possible cell: the star goes in B9.