Deduza

2026-10-15

Solutions · Patrol

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Easy · 6×6

🔦 Patrol · Easy

You cracked: The Case of the Swapped Umbrella

🦉 How to solve it
  1. The witness in the building at row 1, column 1 sees no cells (0): on every street next to the building, a suspect blocks the view right at the first cell.
  2. The witness in the building at row 1, column 6 sees no cells (0): on every street next to the building, a suspect blocks the view right at the first cell.
  3. The witness in the building at row 2, column 1 sees 1 cell in all. Taking away what it sees on its other streets, downward leaves 0 cells: a suspect blocks the view at the next cell.
  4. The witness in the building at row 5, column 4 sees no cells (0): on every street next to the building, a suspect blocks the view right at the first cell.
  5. The witness in the building at row 4, column 1 sees 3 cells in all. Taking away what it sees on its other streets, downward leaves 1 cell: a suspect blocks the view at the next cell.
Medium · 7×7

🔦 Patrol · Medium

You cracked: The Case of the Robbed Clothesline

🦉 How to solve it
  1. The witness in the building at row 1, column 6 sees no cells (0): on every street next to the building, a suspect blocks the view right at the first cell.
  2. The witness in the building at row 3, column 3 sees 5 cells, which is every cell on its streets: none of those streets has a suspect.
  3. The witness in the building at row 4, column 6 sees 1 cell in all. Taking away what it sees on its other streets, downward leaves 0 cells: a suspect blocks the view at the next cell.
  4. The witness in the building at row 1, column 2 sees 6 cells. Adding up the least and the most it can see on its other streets, the view downward is boxed in. These cells are clear.
  5. The witness in the building at row 7, column 2 sees 2 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. The suspect is here.
  6. The witness in the building at row 1, column 2 sees 6 cells in all. Taking away what it sees on its other streets, to the left leaves 1 cell: the whole street, so it is empty.
  7. The witness in the building at row 5, column 3 sees 2 cells in all. Taking away what it sees on its other streets, downward leaves 1 cell: the whole street, so it is empty.
  8. The witness in the building at row 7, column 2 sees 2 cells in all. Taking away what it sees on its other streets, to the left leaves 1 cell: the whole street, so it is empty.
  9. The witness in the building at row 7, column 4 sees 1 cell. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
  10. The witness in the building at row 7, column 4 sees 1 cell in all. Taking away what it sees on its other streets, to the right leaves 0 cells: a suspect blocks the view at the next cell.
  11. Suspect count: there are 8 in all and each stretch of street hides at most one. The numbers only add up this way. The suspect is here.
  12. The stretch of street on row 2 needs a suspect and only one cell is left for it. The suspect is here.
  13. The stretch of street on row 4 needs a suspect and only one cell is left for it. The suspect is here.
Hard · 8×8

🔦 Patrol · Hard

You cracked: The Case of the Empty Pastry

🦉 How to solve it
  1. The witness in the building at row 1, column 3 sees 2 cells, which is every cell on its streets: none of those streets has a suspect.
  2. The witness in the building at row 1, column 4 sees no cells (0): on every street next to the building, a suspect blocks the view right at the first cell.
  3. The witness in the building at row 1, column 5 sees 2 cells in all. Taking away what it sees on its other streets, to the right leaves 1 cell: a suspect blocks the view at the next cell.
  4. The witness in the building at row 3, column 5 sees 3 cells. Adding up the least and the most it can see on its other streets, the view to the left is boxed in. These cells are clear.
  5. The witness in the building at row 5, column 6 sees 2 cells. Adding up the least and the most it can see on its other streets, the view to the right is boxed in. These cells are clear.
  6. The witness in the building at row 7, column 3 sees 3 cells. Adding up the least and the most it can see on its other streets, the view to the left is boxed in. These cells are clear.
  7. The witness in the building at row 8, column 1 sees 5 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
  8. The witness in the building at row 8, column 1 sees 5 cells. Adding up the least and the most it can see on its other streets, the view to the right is boxed in. These cells are clear.
  9. The witness in the building at row 7, column 3 sees 3 cells in all. Taking away what it sees on its other streets, upward leaves 0 cells: a suspect blocks the view at the next cell.
  10. The witness in the building at row 7, column 4 sees 3 cells. Adding up the least and the most it can see on its other streets, the view to the right is boxed in. These cells are clear.
  11. The witness in the building at row 8, column 6 sees 3 cells. Adding up the least and the most it can see on its other streets, the view to the left is boxed in. These cells are clear.
  12. The witness in the building at row 8, column 1 sees 5 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
  13. If a suspect stood here, the witness in the building at row 3, column 5 could no longer see 3 cells. So this cell is clear.
  14. The stretch of street on column 6 needs a suspect and only one cell is left for it. The suspect is here.
  15. The witness in the building at row 5, column 6 sees 2 cells in all. Taking away what it sees on its other streets, to the right leaves 1 cell: a suspect blocks the view at the next cell.
  16. Trying every way for the witness in the building at row 2, column 3 to see 2 cells, without two suspects seeing each other, these cells always come out the same. These cells are clear.
  17. Trying every way for the witness in the building at row 7, column 4 to see 3 cells, without two suspects seeing each other, these cells always come out the same. The suspect is here.
  18. Trying every way for the witness in the building at row 3, column 5 to see 3 cells, without two suspects seeing each other, these cells always come out the same. The suspect is here.
  19. The stretch of street on column 3 needs a suspect and only one cell is left for it. The suspect is here.
  20. The witness in the building at row 2, column 3 sees 2 cells in all. Taking away what it sees on its other streets, to the left leaves 1 cell: a suspect blocks the view at the next cell.
  21. The witness in the building at row 8, column 1 sees 5 cells in all. Taking away what it sees on its other streets, to the right leaves 0 cells: a suspect blocks the view at the next cell.
  22. The witness in the building at row 7, column 4 sees 3 cells in all. Taking away what it sees on its other streets, to the right leaves 1 cell: a suspect blocks the view at the next cell.
  23. The witness in the building at row 8, column 6 sees 3 cells in all. Taking away what it sees on its other streets, to the right leaves 0 cells: a suspect blocks the view at the next cell.
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