Deduza

2026-10-22

Solutions · Constellation

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Easy · 6×6

🌌 Constellation · Easy #8

You discovered: The Melancholic Raccoon

1
🦉 How to solve it
  1. The red nebula has only one possible cell: the star goes in D3.
  2. The pink nebula has only one possible cell: the star goes in A2.
  3. The blue nebula has only one possible cell: the star goes in B4.
  4. The teal nebula has only one possible cell: the star goes in C6.
  5. The amber nebula has only one possible cell: the star goes in E1.
  6. Row 5 has only one possible cell: the star goes in F5.
Medium · 8×8

🌌 Constellation · Medium #8

You discovered: The Lost Penguin

0
🦉 How to solve it
  1. The teal nebula has only one possible cell: the star goes in F2.
  2. The telescope at D2 already sees all its stars: its other neighbors stay empty.
  3. Every possible cell of the lime nebula is in column H: the rest of that column stays empty.
  4. Every possible cell of the brown nebula is in column G: the rest of that column stays empty.
  5. The amber nebula has only one possible cell: the star goes in E7.
  6. Row 1 only has possible cells in the pink nebula: that nebula's star is here, so the rest of it stays empty.
  7. Row 3 has only one possible cell: the star goes in A3.
  8. Row 1 has only one possible cell: the star goes in B1.
  9. Row 8 has only one possible cell: the star goes in C8.
  10. Row 6 has only one possible cell: the star goes in H6.
  11. Row 5 has only one possible cell: the star goes in D5.
  12. Row 4 has only one possible cell: the star goes in G4.
Hard · 9×9

🌌 Constellation · Hard #8

You discovered: The Lovesick Toaster

1
🦉 How to solve it
  1. The lime nebula has only one possible cell: the star goes in G3.
  2. A star in C4 would break the count of the telescope at A3: C4 stays empty.
  3. A star in D4 would break the count of the telescope at A3: D4 stays empty.
  4. A star in E4 would break the count of the telescope at A3: E4 stays empty.
  5. A star in B8 would leave the red nebula with no possible cell: B8 stays empty.
  6. A star in E8 would leave the violet nebula with no possible cell: E8 stays empty.
  7. A star in D9 would leave the red nebula with no possible cell: D9 stays empty.
  8. A star in E7 would leave the violet nebula with no possible cell: E7 stays empty.
  9. The teal nebula and the amber nebula fit entirely in column A and column B: no other nebula can have a star there.
  10. Every possible cell of the red nebula is in column C: the rest of that column stays empty.
  11. A star in I4 would break the count of the telescope at A3: I4 stays empty.
  12. Row 4 only has possible cells in the amber nebula: that nebula's star is here, so the rest of it stays empty.
  13. A star in D8 would leave column C with no possible cell: D8 stays empty.
  14. A star in E6 would leave the violet nebula with no possible cell: E6 stays empty.
  15. Column H and column I only have cells from the brown nebula and the pink nebula: those nebulas have no star elsewhere.
  16. The violet nebula, the pink nebula and the red nebula fit entirely in row 7, row 9 and row 8: no other nebula can have a star there.
  17. Column B has only one possible cell: the star goes in B4.
  18. Column A has only one possible cell: the star goes in A6.
  19. Column F has only one possible cell: the star goes in F1.
  20. Column E has only one possible cell: the star goes in E9.
  21. Row 7 has only one possible cell: the star goes in I7.
  22. Row 2 has only one possible cell: the star goes in D2.
  23. Row 5 has only one possible cell: the star goes in H5.
  24. Row 8 has only one possible cell: the star goes in C8.
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