Easy · 6×6
🔦 Patrol · Easy #7
You cracked: The Case of Yesterday's Croquette
🦉 How to solve it
- The witness in the building at row 4, column 2 sees no cells (0): on every street next to the building, a suspect blocks the view right at the first cell.
- The witness in the building at row 3, column 2 sees 2 cells in all. Taking away what it sees on its other streets, upward leaves 0 cells: a suspect blocks the view at the next cell.
- The witness in the building at row 1, column 2 sees 4 cells in all. Taking away what it sees on its other streets, to the right leaves 3 cells: a suspect blocks the view at the next cell.
- The witness in the building at row 2, column 5 sees 6 cells in all. Taking away what it sees on its other streets, downward leaves 3 cells: a suspect blocks the view at the next cell.
- The witness in the building at row 3, column 4 sees 6 cells in all. Taking away what it sees on its other streets, to the right leaves 1 cell: a suspect blocks the view at the next cell.
Medium · 7×7
🔦 Patrol · Medium #7
You cracked: The Case of the Empty Pastry
🦉 How to solve it
- The witness in the building at row 4, column 3 sees 3 cells, which is every cell on its streets: none of those streets has a suspect.
- The witness in the building at row 1, column 1 sees 1 cell. Adding up the least and the most it can see on its other streets, the view downward is boxed in. These cells are clear.
- The witness in the building at row 1, column 4 sees 5 cells. Adding up the least and the most it can see on its other streets, the view downward is boxed in. These cells are clear.
- The witness in the building at row 2, column 7 sees 2 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
- The witness in the building at row 2, column 7 sees 2 cells in all. Taking away what it sees on its other streets, to the left leaves 1 cell: a suspect blocks the view at the next cell.
- The stretch of street on column 1 needs a suspect and only one cell is left for it. The suspect is here.
- The witness in the building at row 1, column 1 sees 1 cell in all. Taking away what it sees on its other streets, to the right leaves 0 cells: a suspect blocks the view at the next cell.
- The witness in the building at row 4, column 2 sees 4 cells in all. Taking away what it sees on its other streets, downward leaves 1 cell: a suspect blocks the view at the next cell.
- The witness in the building at row 6, column 1 sees 1 cell in all. Taking away what it sees on its other streets, downward leaves 1 cell: the whole street, so it is empty.
- The witness in the building at row 1, column 4 sees 5 cells. Adding up the least and the most it can see on its other streets, the view downward is boxed in. These cells are clear.
- Suspect count: there are 9 in all and each stretch of street hides at most one. The numbers only add up this way. The suspect is here.
- If a suspect stood here, the witness in the building at row 1, column 4 could no longer see 5 cells. So this cell is clear.
- The stretch of street on column 6 needs a suspect and only one cell is left for it. The suspect is here.
- The witness in the building at row 1, column 4 sees 5 cells in all. Taking away what it sees on its other streets, downward leaves 3 cells: a suspect blocks the view at the next cell.
- The stretch of street on column 6 needs a suspect and only one cell is left for it. The suspect is here.
- The stretch of street on column 7 needs a suspect and only one cell is left for it. The suspect is here.
Hard · 8×8
🔦 Patrol · Hard #7
You cracked: The Case of the Empty Pastry
🦉 How to solve it
- The witness in the building at row 8, column 1 only looks down the street to the right and sees 5 cells there: a suspect blocks the view at the next cell.
- The witness in the building at row 5, column 7 sees 5 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
- The witness in the building at row 6, column 3 sees 6 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
- The witness in the building at row 7, column 2 sees 3 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
- The witness in the building at row 7, column 4 sees 3 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
- The witness in the building at row 7, column 4 sees 3 cells. Adding up the least and the most it can see on its other streets, the view to the right is boxed in. These cells are clear.
- Trying every way for the witness in the building at row 6, column 3 to see 6 cells, without two suspects seeing each other, these cells always come out the same. These cells are clear.
- Trying every way for the witness in the building at row 6, column 6 to see 4 cells, without two suspects seeing each other, these cells always come out the same. The suspect is here.
- The witness in the building at row 6, column 3 sees 6 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. These cells are clear.
- The witness in the building at row 7, column 4 sees 3 cells. Adding up the least and the most it can see on its other streets, the view upward is boxed in. The suspect is here.
- The stretch of street on column 2 needs a suspect and only one cell is left for it. The suspect is here.
- The stretch of street on column 3 needs a suspect and only one cell is left for it. The suspect is here.
- The witness in the building at row 6, column 3 sees 6 cells in all. Taking away what it sees on its other streets, downward leaves 0 cells: a suspect blocks the view at the next cell.
- Trying every way for the witness in the building at row 2, column 6 to see 2 cells, without two suspects seeing each other, these cells always come out the same. The suspect is here.
- The stretch of street on column 7 needs a suspect and only one cell is left for it. The suspect is here.
- The witness in the building at row 5, column 7 sees 5 cells in all. Taking away what it sees on its other streets, to the right leaves 0 cells: a suspect blocks the view at the next cell.
- Suspect count: there are 12 in all and each stretch of street hides at most one. The numbers only add up this way. The suspect is here.